Math, asked by aarohisharma83644, 4 months ago


x + y - 8 \div 2 = x + 2y - 14 \div 3 = 3x + y - 12 \div 11

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Answered by Anonymous
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Answer:

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Step-by-step explanation:

 \frac{x + y - 8}{2}  =  \frac{x + 2y - 14}{3}  =  \frac{3 x + y - 12}{11}  \\  \\ \frac{(x + y - 8) \times 33}{2 \times 33}=  \frac{(x + 2y - 14) \times 22}{3 \times 22} ) =  \frac{(3 x + y - 12) \times 6}{11 \times 6})  \\  \\  \frac{33x + 33y - 264}{66}  =  \frac{22x + 44y - 308}{66}  =  \frac{18x + 6y - 72}{66}  \\  \\cancelling \:  \:  denominators  \:  \: ---[since \:  \:  denominators \:  \:  are  \:  \: same] \\  \\ 33x + 33y - 264 = 22x + 44y - 308 = 18x + 6y - 72 \\  \\ 33x - 22x - 18x = 44y - 33y - 6y =  - 72 + 308 + 264 \\  \\  - 7x = 5y = 500

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