![(x - y)(x + y) = 1 (x - y)(x + y) = 1](https://tex.z-dn.net/?f=%28x+-+y%29%28x+%2B+y%29+%3D+1)
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Answer:
Given:-
Solution:-
In this we will multiply the bracket variables, let's take x-y for multiplication
Now,we will subtract or add the common terms according to their symbols
xy and yx or xy will be canceled because of having different signs
Answer:-
x²+y² = 1
:)
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