Question

$x + y + z = 0 \: then \: shows \: that \: (a - b) ^{3} + (b - c) ^{3} + (c - a)^{3} = 3(a - b)(b - c)(c - a)$
hey guys please don't keep any silly answer to get the points I want the answer fast please help me guys​.

Answer 1

Answer:

it's zero hope this helps

Answer 2

■ ANSWER ■

We have,

• a+b+c=5
• ab+bc+ca=10

 

Since,

• (a+b+c)2=25
• a2+b2+c2+2(ab+bc+ca)=25
• a2+b2+c2+2×10=25
• a2+b2+c2=5

 

We know that,

• a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−(ab+bc+ca))
• a3+b3+c3−3abc=(5)×(5−10)
• a3+b3+c3−3abc=5×−5
• a3+b3+c3−3abc=−25

HENCE PROVED

■ HOPE IT HELPS YOU ■