![(x + y + z)2 (x + y + z)2](https://tex.z-dn.net/?f=%28x+%2B+y+%2B+z%292)
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Answered by
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• (x + y + z)²
=> x² + y² + 2xy + 2yz + 2zx
What you need to know :-
• (x + y)²
=> x² + y² + 2xy
• (x - y)²
=> x² + y² - 2xy
• (x + y)³
=> x³ + y³ + 3x²y + 3xy²
• (x - y)³
=> x³ - y³ - 3x²y + 3xy²
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