Question

$x2 + 3 \sqrt{3x} + 6 =$
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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

${x}^{2} + 3 \sqrt{3x} + 6 \\ {x}^{2} + 3( \sqrt{3} )( \sqrt{x} ) + 6 \\ \\ use \: the \: equation \: \\ \\ x = \frac{ - b \: + - \sqrt{ {b }^{2} - 4ac } }{2a} \\ \\ where \: \: \\ a =1 \\ b = 3 \sqrt{3} \\ c = 6 \\ \\ x = \frac{ - 3 \sqrt{3} + - \sqrt{( {3 \sqrt{3}) }^{2} - 4(1)(6) } }{2 }$