Question

$(x2 + 3)(x4 - 9)$
differentiate with respect to x​

Answer 1

Answer:

6X^5+12X^3-18X

Explanation:

(X^2+3)(x^4-9) = X^6+3x^4-9x^2-27

Now let y = X^6+3x^4-9x^2-27

we can get after differentiate with respect to X

dy/dx= 6X^5+12X^3-18X

Answer 2

Use Product Rule,

$\frac{d(rs)}{dx}=r\frac{d(s)}{dx}+s\frac{d(r)}{dx}$

Given: $(x^2+3)(x^4-9)$

$\frac{d((x^2+3)(x^4-9))}{dx}=(x^2+3)\frac{d(x^4-9)}{dx}+(x^4-9)\frac{d(x^2+3)}{dx}$

$\frac{d((x^2+3)(x^4-9))}{dx}=(x^2+3)(4x^3)+(x^4-9)(2x)$

$\frac{d((x^2+3)(x^4-9))}{dx}=4x^5+12x^3+2x^5-18x$

#SPJ2