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1
x^2 +5x +6
=>>> x^2'+2x +3x +6
=>>>> x(x+2)+ 3(x+2)
=>>>> (x+3) (x+2)
=>>> x+3= 0 & x+2= 0
=>>> x=-3 & x= -2 ans
Answered by
0
if x+3=0
then :-
x+5=0
x=-5
if x+2=0
then:-
x+2=0
x=-2
I hope it help you
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thanks for asking....
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