Question

$x2 - x - 182 = 0$


​

Answer 1

Answer:

Solution for x2+x-182=0 equation:

x2+x-182=0

We add all the numbers together, and all the variables

x^2+x-182=0

a = 1; b = 1; c = -182;

Δ = b2-4ac

Δ = 12-4·1·(-182)

Δ = 729

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=−b−Δ√2ax2=−b+Δ√2a

Δ−−√=729−−−√=27

x1=−b−Δ√2a=−(1)−272∗1=−282=−14

x2=−b+Δ√2a=−(1)+272∗1=262=13

Step-by-step explanation:

follow me and I follow you and Mark me in brainlist

Answer 2

Answer:

mark it as brainliest

follow me...