Question

$x3+3x2-5x+36$determine whether (x+4) is a factor of  

Answer 1

Lets assume that x+4 is a factor
x=-4
f(-4)=-64+48+20+36=-64+  104≠0
  hence its a contradiction.
so x+4 is not a factor.

Answer 2

Answer:

It is not a factor

Step-by-step explanation:

Equate (x+4) to 0

x+4 = 0

x = -4

now, substitute the value of x into the equation

$(-4^{3} ) + 3(-4^{2} ) - 5x + 36$

Now we simplify

$-64 + 48 + 20 + 36$

The answer is $40$.

Therefore  $(x+4)$ is not a factor of $x^{3} + 3x^{2} + 5x + 36$ because it has a remainder.