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We know that,
a³ – b³ = (a – b) (a² + b² + ab)
x3 – 64y3 = x³ – (4y)³
Here, a = x and b = 4y
Now, substituting in the above formula, we get
x³ – (4y)³ = (x – 4y) [x² + x(4y) + (4y)²]
= (x – 4y) (x² + 4xy + 16y²)
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