Question

$xcube + 2 {x}^{2} { - x - 2}^$
​

Answer 1

Answer:

1, -1, -2

Explanation:

let,

f(x)= x³ + 2x² -x -2

to obtain the roots of the equation,

f(x)=0

∴x³+2x²-x-2=0

now,

  x²(x+2)-1(x+2)=0,      ∵taking x² and -1 common from respective terms

⇒(x+2)(x²-1)=0

⇒(x+2)(x-1)(x+1)=0,        ∵as, a²-b²=(a+b)(a-b)

if x+2=0,

⇒x= -2

if x+1=0

⇒x= -1

if x-1=0

⇒x=1

∴ roots of equation f(x)=0 are 1, -1, -2

Hope it helps!!

plz mark BRAINLIEST :)