Question

$xy + zx + y ^{2} - z ^{2}$
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Answer 1

Answer:

$(y+z)(x+y-z)$

Step-by-step explanation:

Tip : If terms share same factor,

then we get (same factor) × (sum of the rest)

In other words $ma+mb=m(a+b)$.

Two terms xy and zx shares same factor, x.

The rest are y and z.

Therefore, $(xy+zx)=x(y+z)$

Now, we have  $y^2-z^2$ and it is $(y+z)(y-z)$ by identity.

Now, $x(y+z)$ and $(y+z)(y-z)$ shares same factor, y+z.

The rest are $x$ and $y-z$.

Therefore, we get $(y+z)(x+y-z)$.

Answer 2

Step-by-step explanation:

hope it's helpful

(y+z)(x+y−z)

Step-by-step explanation:

Tip : If terms share same factor,

then we get (same factor) × (sum of the rest)

In other words ma+mb=m(a+b)ma+mb=m(a+b) .

Two terms xy and zx shares same factor, x.

The rest are y and z.

Therefore, (xy+zx)=x(y+z)(xy+zx)=x(y+z)

Now, we have y^2-z^2y

2

−z

2

and it is (y+z)(y-z)(y+z)(y−z) by identity.

Now, x(y+z)x(y+z) and (y+z)(y-z)(y+z)(y−z) shares same factor, y+z.

hope it's helpful

The rest are xx and y-zy−z .

Therefore, we get (y+z)(x+y-z)(y+z)(x+y−z