Question

$( {y }^{2} - 7y + 12)(y + 4) \div (y - 4)$
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Answer 1

Answer:

tex_y_^2_7y12(y+ljh uq&shb) ans

Answer 2

Step-by-step explanation:

$\frac{(y { }^{2} - 7y + 12) \times (y + 4) }{y - 4}$

$\frac{(y {}^{2} \sf\red{ - 3y - 4y} + 12) \times (y + 4)}{y - 4}$

$\frac{(\sf\red{y \times (y - 3)} - 4y + 12) \times (y + 4)}{y - 4}$

$\frac{(y \times (y - 3) - \sf\red{4(y - 3)}) \times (y + 4)}{y - 4}$

$\frac{\sf\red{(y - 3) \times (y - 4) } \times (y + 4)}{y - 4}$

$(y - 3) \times (y + 4)$

Multiply the Parentheses

$\sf\red{y {}^{2} + 4y - 3y - 12}$

Collect Like Terms

$y {}^{2} + \sf\red{4y {}^{2} - 3y} - 12 \\ = > y {}^{2} + \sf\red{y} - 12$

Answer ⤵

$\;\large{\boxed{\bf{\green{y {}^{2} + y - 12}}}}$

$\sf\blue{hope \: this \: helps \: you!! \: }$

@Mahor2111