Answers
Answered by
1
Answer:
Answer
Given that: y
3
−3y
2
+2y−6−xy+3x
=(y
3
−3y
2
)+(2y−6)+(−xy+3x), (group pair of terms)
=y
2
(y−3)+2(y−3)−x(y−3), (factor each binomials)
=(y−3)(y
2
+2−x) , (factor out common factor (y−3))
The common factors of y
3
−3y
2
+2y−6−xy+3x are (y−3)(y
2
+2−x)
Similar questions
Math,
2 months ago
English,
2 months ago
Social Sciences,
2 months ago
Social Sciences,
4 months ago
Chemistry,
10 months ago
Social Sciences,
10 months ago