Math, asked by tanveeralam4120, 7 months ago

${y}^{3} - \sqrt{3y}$

Answers

Answered by jaidansari248

0

Answer:

${y}^{3} - \sqrt{3y} \\ = {y}^{3} - {(3y)}^{ \frac{1}{2} } = > {y}^{5} - \sqrt[2]{3} \times y$

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