Question

[tex]y = 3^x ,
find
d^2y / dx^2[/tex]

Answer 1

$\huge\color{Black}\boxed{\colorbox{yellow}{❀Answer❀}}$

$y = {3}^{x} \\ \frac{dy}{dx} = {3}^{x} log3 \\ \frac{d}{dx} \frac{dy}{dx} = {3}^{x} \frac{d}{dx} log3 + log3 \frac{d}{dx} {3}^{x} \\ \frac{ {d}^{2} y}{ {dx}^{2} } = {3}^{x} .0 + log3. {3}^{x} log3 \\ \frac{ {d}^{2} y}{ {dx}^{2} } = ( {log3})^{2} {3}^{x}$

Answer 2

Refer the attachment for the answer ✔️