Answers
Answered by
0
hello dear....♥♥
your answer is here.....⭐⭐⭐
y = a√2(sin 2πt/T + cos 2πt/T)
we know, sinx + cosx = √2sin(x + π/4)
so, y = a√2 × √2sin(2πt/T + π/4)
y = 2a sin(2πt/T + π/4)
compare this equation with standard equation of simple harmonic motion.
e.g., y = Asin(2πt/T + \PhiΦ )[/tex]
where A is amplitude, T is time period and \PhiΦ is phase angle.
hence, amplitude, A = 2a
time period is T
and phase angle of wave , \PhiΦ = π/4
your answer is here.....⭐⭐⭐
y = a√2(sin 2πt/T + cos 2πt/T)
we know, sinx + cosx = √2sin(x + π/4)
so, y = a√2 × √2sin(2πt/T + π/4)
y = 2a sin(2πt/T + π/4)
compare this equation with standard equation of simple harmonic motion.
e.g., y = Asin(2πt/T + \PhiΦ )[/tex]
where A is amplitude, T is time period and \PhiΦ is phase angle.
hence, amplitude, A = 2a
time period is T
and phase angle of wave , \PhiΦ = π/4
aastha4865:
aastha sharna
Similar questions