Question

$y = cos3x sin4x$
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Answer 1

Answer:

First derivative = cos (3x) [4 cos 4x] + sin (4x) [-3sin 3x]

= 4 cos 4x cos 3x - 3 sin 4x sin 3x

Second derivative

= 4 [ cos4x(-3 sin 3x)+ cos3x(-4sin4x] -3[ sin4x(3cos3x) + sin3x(4cos4x)]

= -24 sin3x cos4x - 25 sin 4x cos 3x

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