Question

$y \: + \frac{3}{2} = 5$
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Answer 1

Step-by-step explanation:

$y + \frac{3}{2} = 5 \\ \\ y + 3 = 5 \times 2 \\ \\ = y + 3 = 10 \\ \\ y = 10 - 3 \\ \\ = 7$

Answer 2

Given:-

$\sf{y}$+ $\sf\dfrac{3}{2}$ = 5

To find :-

Value of y

Solution:-

$\sf{y}$+ $\sf\dfrac{3}{2}$ = 5

Take LCM in LHS

$\sf\dfrac{2y+3}{2}$=5

Do cross multiplication

2y + 3 = 2 (5)

2y + 3 = 10

Transpose 3 to RHS

2y = 10-3

2y = 7

y = $\sf\dfrac{7}{2}$

Verification:-

Substuite value of y to get LHS=RHS

$\sf{y}$+ $\sf\dfrac{3}{2}$ = 5

$\sf\dfrac{7}{2}$ + $\sf\dfrac{3}{2}$ = 5

$\sf\dfrac{7+3}{2}$=5

$\sf\dfrac{10}{2}$=5

5 = 5

LHS = RHS

verified

So, the value of x is $\sf\dfrac{7}{2}$