Question

$y = log( \frac{a - x}{a + x} )$
find the second derivative

Answer 1

solution of ur question.....

Answer 2

y1=$\frac{a+x}{a-x}$ * $\frac{(a+x)(-1)+(a-x)}{(a+x)^{2} }$
y1=$\frac{-x^2}{a^2-x^2}$
y2=[tex] \frac{(a^2-x^2)(-2x)+(-x^2)(-2x)}{(a^2-x^2)^2} = \frac{4x^3-a^2}{(a^2-x^2)^2} [/tex]

hope this helps!