Question

$y = sec \sqrt{x \: } then \: dy \div dx$
​

Answer 1

Answer:

Given

$y = \sec( \sqrt{x} )$

Therfore

$\frac{dy}{dx} = \frac{d}{dx} ( \sec( \sqrt{x} ) \\ \frac{dy}{dx} = \sec( \sqrt{x}) \times \tan( \sqrt{x} ) \times \frac{d}{dx} ( \sqrt{x} ) \\ \frac{dy}{dx} = \sec( \sqrt{x} ) \tan( \sqrt{x} ) \times \frac{1}{2 \sqrt{x} } \\ \frac{dy}{dx} = \frac{ \sec( \sqrt{x} ) \tan( \sqrt{x} ) }{2 \sqrt{x} }$

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