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Answer:
(a
3
1
−x
3
1
)
3
dx=∫(a−3a
3
2
x
3
1
+3a
3
1
x
3
2
−x
3
)dx=
=ax-3a^{\frac{2}{3}}\frac{x^{\frac{1}{3}+1}}{\frac{1}{3}+1}+3a^{\frac{1}{3}}\frac{x^{\frac{2}{3}+1}}{\frac{2}{3}+1}-\frac{x^4}{4}+C==ax−3a
3
2
3
1
+1
x
3
1
+1
+3a
3
1
3
2
+1
x
3
2
+1
−
4
x
4
+C=
=ax-3a^{\frac{2}{3}}\frac{x^{\frac{4}{3}}}{\frac{4}{3}}+3a^{\frac{1}{3}}\frac{x^{\frac{5}{3}}}{\frac{5}{3}}-\frac{x^4}{4}+C==ax−3a
3
2
3
4
x
3
4
+3a
3
1
3
5
x
3
5
−
4
x
4
+C=
=ax-\frac{9}{4}a^{\frac{2}{3}}xx^{\frac{1}{3}}+\frac{9}{5}a^{\frac{1}{3}}xx^{\frac{2}{3}}-\frac{x^4}{4}+C=ax−
4
9
a
3
2
xx
3
1
+
5
9
a
3
1
xx
3
2
−
4
x
4
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