Question

$zeros \: of \: the \: polynomial \: {x}^{2} - 2 \sqrt{3} x + 2 \: ar$

Answer 1

zeroes of the polynomial is
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Answer 2

If we want zeroes, polynomial must be equal to 0 .



Your question needs few corrections :



Correct Equation : x² - 2√3 x + 2




On comparing the given equation with a²x + bx c = 0 , we get the following information :


a = 1
b = - 2√3
c = 2



By Quadratic Formula,


x = $\dfrac{-b \pm \sqrt{b^{2}-4ac}}{2a}$



x = $\dfrac{-(-2 \sqrt{3}) \p\sqrt{{(-2\sqrt{3}})^{2}-8}}{2}$


x = $\dfrac{2 \sqrt{3} \pm \sqrt{12-8}}{2}$


x = $\dfrac{2 \sqrt{3} \pm 2 }{2}$


x = √3 ± 1



Therefore zeroes of the given polynomial is √3 + 1 or √3 - 1