Question

text 11 x square - 26 x minus 21 is equal to zero solve from square in both side method

Answer 1

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Answer 2

Hope u like my process
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For f(x) = 11x² - 26x - 21 to be a perfect square, the f(x) should be in form of x² - 2ax +a²

So,
$= > 11 {x}^{2} - 26x - 21 = 0 \\ \\ = > 11 {x}^{2} - 26x = 21 \\ \\ = > {x}^{2} - \frac{26}{11} x = \frac{21}{11 } \\ \\ = > {x}^{2} - 2 \times \frac{13}{11} x + { (\frac{13}{11} )}^{2} = \frac{21}{11} + {( \frac{13}{11} )}^{2} \\ \\ = > {(x - \frac{13}{11} )}^{2} = \frac{21}{11} + \frac{169}{11} = \frac{(21 \times 11) + 169}{121} \\ \\ = > {(x - \frac{13}{11} )}^{2} = \frac{231 + 169}{121} = \frac{400}{121} \\ \\ = > x - \frac{13}{11} = \sqrt{ \frac{20 \times 20}{11 \times 11} } = \frac{20}{11} \\ \\ = > \bf \: x = \frac{20}{11} + \frac{13}{11} = \frac{33}{11} = \underline{ 3}$
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