Question

(text) {(2^3x+ 1)+10}÷7=6​

Answer 1

Answer:

$\{ ({2}^{3x + 1} ) + 10 \} \div 7 = 6 \\ \frac{\{ ({2}^{3x + 1} ) + 10 \}}{7} = 6 \\ \{ ({2}^{3x + 1} ) + 10 \} = 7 \times 6 \\ \{ ({2}^{3x + 1} ) + 10 \} = 42 \\ {2}^{3x + 1} = 42 - 10 \\ {2}^{3x + 1} = 32 \\ {2}^{3x + 1} = {2}^{5} \\ 3x + 1 = 5 \\ 3x = 5 - 1 \\ 3x = 4 \\ x = \frac{4}{3}$