tf ( alpha+ beta)^ * =( alpha- beta)( alpha^ 2 + beta^ 2 + alpha beta) and (alpha + beta) ^ 0 = alpha ^ 2 + beta ^ 2 - 2alpha * beta , then the value of sqrt([(3 + 1) ^ theta + 2] ^ 0)
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Step-by-step explanation:
Answer
α=2βandα+β=90
∘
∴α=60
∘
andβ=30
∘
∴cos
2
α+sin
2
β=cos
2
60
∘
+sin
2
30
∘
=
4
1
+
4
1
=
2
1
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