Question

Tf Numerator is multiplied by 3 and 3
is subtracted from the denominator then
the fraction
fraction obtained is 18/11
frame
an equation​

Answer 1

Answer:

The correct answer is

Step-by-step explanation:

Answer:

Original fraction = 6/14 .

Step-by-step explanation:

Let numerator be x and denominator be y.

First condition says that If numerator is multiplied by 3 and 3 is subtracted from the denominator then the fraction obtained is 18/11 i.e.;

\frac{x*3}{y-3}= \frac{18}{11}

y−3

x∗3

=

11

18

33 * x = 18(y - 3)

33*x = 18*y - 54

11*x = 6*y - 18 ---------- [Equation 1]

Second condition says that If numerator is increased by 8 and denominator is doubled then the resulting fraction is 1/2, i.e.;

\frac{x+8}{2y} = \frac{1}{2}

2y

x+8

=

2

1

2(x + 8) = 2*y

x + 8 = y

x = y - 8 ----------- [Equation 2]

Now, putting value of x from equation 2 into equation 1, we get;

11(y - 8) = 6*y - 18

11*y - 88 = 6*y - 18

11*y - 6*y = 88 - 18

5*y = 70

y = 14 and so x = 14 - 8 = 6

Therefore, numerator, x = 6 and denominator, y = 14 .