Question

Tge diagnols of a quadrilateral are of length 8 cm and 6 cm.The diagnoks bisect each other 90°. Find the length of each side of the quadrilateral​

Answer 1

Let the ABCD be the quadrilateral.

So, According to the question, we have

AO = OC and OB =OD

Also, Angles made by the intersection of diagonal of it will be 90° each.

Now, in triangle AOB, BOC,COD and AOD, we have

AB^2 = 3^2 + 4^2..... (1) [by Pythagoras theorem]

So, AB = 5 cm

Similarly,

BC = CD = AD = (3^2 + 4^2)^1/2 = 5 cm.