Question

Tge roots of a quadratic equation are equal then 2x^2-kx+1=0 find the value of k

Answer 1

Given the quadratic equation is:

2 x² - kx + 1 = 0

Comparing it with ax²+bx+c=0:-

we get:

a=2,

b=-k

c=1

We know that if a quadratic equation has real and equal roots then :

b² = 4ac

So: (-k)² = 4*2*1

=k²=8

=k√2*4

=k=2√2

The value of k is 2√2

Hope it helps you.

Answer 2

Hlo mate :-

Solution :-

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:- p (x) = 2 x² - kx + 1 = 0


● Comparing it with ax²+bx+c=0:-

we get:

a=2

b= -k

c=1


As we know that if a quadratic equation has real and equal roots then :


b² = 4ac


So: (-k)² = 4*2*1


=k²=8


=k√2*4


=k=2√2


The value of k is = 2√2

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