Question

th 1. In in the experiment of determining thickness of the wire using sorew gauge the readings are, 1.83,1.86,1.85,1.87 and 1.84. Fond the mean thickness.​

Answer 1

Answer:

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Answer 2

Given,

Thickness of wire using screw gauge,

$\[ = 1.83,1.86,1.85,1.87,1.84\]\left$

Solution,

The mean of the given n data,

$\[ = \frac{{\sum n }}{n}\]$

$\[ = \frac{{1.83 + 1.86 + 1.85 + 1.87 + 1.84}}{5}\]$

$\[ = \frac{{9.25}}{5}\]$

$\[ = 1.85\]$

Hence the mean thickness is $\[1.85\]$