Question

th difference between the square of two consicutive numbers is 31 find the numbers​

Answer 1

Answer:

Let 1st con number x

Let 2nd con. number x+1

So,

x+x+1=31

2x+1=31

2x=31-1

x=30/2

x=15

1st con number=x=15

2nd con number=x+1=15+1=16

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Answer 2

★ Assume :

the numbers as x and y

they are consecutive -

x = x

y = x+1

★ Given :

y² - x² = 31

★To find :

the numbers ( x and y)

★ Solution :

by putting the value of y

$(x+1)^2 - x^2 = 31 \\ \\ \\ (\cancel{x^2} + 2x + 1) - \cancel{x^2} = 31 \\ \\ \\ 2x + 1 = 31 \\ \\ \\ 2x = 31-1 \\ \\ \\ 2x = 30 \\ \\ \\ x = \frac{\cancel{30}}{\cancel{2}} \\ \\ \\ x = 15$

therefore , the numbers are -

${\pink{\boxed{x = 15 , y = 16}}}$