Question

Th
e base of triangular field is 880m and height is 550m . Find the area of the field.​

Answer 1

Answer:

Area of triangle =

2

1

× base × height =

2

1

×880×550

=242000m

2

Answer 2

${\underline{\boxed{\mathcal{\pmb{\quad \: GIVEN\qquad}}}}}$

• Base of triangular field is 880 m.
• Height of triangular field is 550 m.

${\underline{\boxed{\mathcal{\pmb{\quad TO \: FIND \qquad}}}}}$

• Area of the field ?

${\underline{\boxed{\mathcal{\pmb{\quad SOLUTION\qquad}}}}}$

We know that,

$\underline{ \boxed{ \pink{ \rm{Area \: of \: ∆ = \frac{1}{2} \times b \times h}}}}$

• Now, Substitute the values :-

$\implies{ \rm{Area \: of \: ∆ = \frac{1}{ \cancel2} \times \cancel{880 } \times 550}}$

$\implies{ \rm{Area \: of \: ∆ = 440 \times 550}}$

$\implies{ \boxed{ \rm{Area \: of \: ∆ = 242000 \: m ^{2} }}}$

• Hence, The Area of ∆ is 242000 m².

______________________________

${ \underline{ \underline{ \sf{ \pmb{ \red{More \: Information}}}}}} :$

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {minipage}{9cm}\\ \dag\quad \small\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}\end{gathered}\end{gathered}\end{gathered}\end{gathered<u>}$