Th eproduct if 2 successive integral multuples of 5 is 300.determine the multiples
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Answered by
1
Hi ,
Let m , ( m + 5 ) are two successive multiples
5 .
Their product = 300
m( m + 5 ) = 300
i ) m( m + 5 ) = 15 × 20
m( m + 5 ) = 15( 15 + 5 )
compare both sides of the equation
m = 15 ,
m + 5 = 15 + 5 = 20
ii ) m( m + 5 ) = 300
m( m + 5 ) = ( -15 ) × ( - 20 )
m( m + 5 ) = ( -20 )( -20 + 5 )
compare both sides of the equation ,
we can easily conclude that ,
m = -20 ,
m + 5 = -20 + 5 = -15
I hope this helps you.
: )
Let m , ( m + 5 ) are two successive multiples
5 .
Their product = 300
m( m + 5 ) = 300
i ) m( m + 5 ) = 15 × 20
m( m + 5 ) = 15( 15 + 5 )
compare both sides of the equation
m = 15 ,
m + 5 = 15 + 5 = 20
ii ) m( m + 5 ) = 300
m( m + 5 ) = ( -15 ) × ( - 20 )
m( m + 5 ) = ( -20 )( -20 + 5 )
compare both sides of the equation ,
we can easily conclude that ,
m = -20 ,
m + 5 = -20 + 5 = -15
I hope this helps you.
: )
Answered by
1
Let numbers are, 5x and (5x + 5)
===============
Their product = 300
5x(5x + 5) = 300
25x² + 25x = 300
25x² + 25x - 300 = 0
x² + x - 12 = 0
x² + (4 - 3)x - 12 = 0
x² + 4x - 3x - 12 = 0
x(x + 4) - 3(x + 4) = 0
(x + 4)(x - 3) =0
x = -4 or x = 3
Taking x as 3 [ positive value]
======================
Numbers are :
• 5x = 5(3)=15
• 5x + 5 = 15 + 5 = 20
I hope this will help you
(-:
===============
Their product = 300
5x(5x + 5) = 300
25x² + 25x = 300
25x² + 25x - 300 = 0
x² + x - 12 = 0
x² + (4 - 3)x - 12 = 0
x² + 4x - 3x - 12 = 0
x(x + 4) - 3(x + 4) = 0
(x + 4)(x - 3) =0
x = -4 or x = 3
Taking x as 3 [ positive value]
======================
Numbers are :
• 5x = 5(3)=15
• 5x + 5 = 15 + 5 = 20
I hope this will help you
(-:
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