Question

th find the nth derivative of x² sin 5x.​

Answer 1

Step-by-step explanation:

Answer:

y_n=\left(x^2-n^2+n\right)sin\left(x+\frac{n\pi }{2}\right)-2nx\cdot cos\left(x+\frac{n\pi }{2}\right)yn=(x2−n2+n)sin(x+2nπ)−2nx⋅cos(x+2nπ

Here given y=x²sin(x)=(sinx)x²=u(x)v(x) are the two functions of x

so we got u(x)=sinx

and v(x)=x²

apply Leibnitzs Rule with u and v as function of x

Please find the complete solution in the pic attached