Question

Th greatest number of two digit divisible by 12 and 18 is

Answer 1

$\huge \blue{answer}$

$solve = = > 18 \: and \: 12 \: divisible \: by \\ \\ = > 12 = 12,6,4,2,1 \\ \\ = > 18 = 18,9,6,2,1 \\ \\ = > so \: 18,12,9 \: can \: not \: be \: divisible \: digits \: of \: 12,18 \\ \\ so \: 6 \: is \: the \: greatest \: number \: for \: 12,18 \: because \: it \: can \: divide \: both \: numbers.$