Question

Th length and breadth of a rectangular field are in ratioof 3:2.if the area of the field is 3456msq find thr cost of fencing at 60 rs per m

Answer 1

l/b = 3/2 
2l = 3b 
l = 3b/2

area of rectangle = length x breadth 
 l x b = 3456
3b/2 x b = 3456
3b$^{2}$ = 6912 
b$^{2}$ = 2304 
b = $\sqrt{2304}$

b= + 48 m   or  b = -48 ( rejected , breadth cant be negative )

l = 3 x 48 / 2
l = 3 x 24 

l= 72 m

perimeter of field = 2 ( l + b )
=> 2 x 120
=240 m 

cost of fencing =  cost per m x perimeter
=> 60 x 240 

=> 14400 rs. 

Hope i helped , mark brainliest if i did it correctly

Answer 2

Let the length of the field be 3x m

Then , it's breadth = 2x m.

So , Area of the field =( Length × Breadth ) sq. unit

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= ( 2x × 3x)m²

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= ( 6x²) m²

But , area = 3456m² ( given )

So, 6x² = 3456 =》x² = $\frac{3456}{6} = 576$

x = $\sqrt{576} = 24.$

So, Length = ( 3 × 24 ) m

⠀⠀⠀⠀⠀⠀⠀= 48 m

⠀⠀ Breadth = ( 2 × 24 )m

⠀⠀⠀⠀⠀⠀⠀⠀= 72 .

Then , Perimeter of field = 2( l + b)

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 2 ( 48 + 72)m

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= ( 2 × 120 )m

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 240 m .

Hence , the cost of fencing = Rs. ( 240 × 60)

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= Rs. 14,580 ans.

$\huge\mathcal\color{teal}Hope\:it\:helps!!$

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