Question

Th solution of triangle pqr is an isosceles triangle with pq = pr = 7 cm and qr = 12 cm. Ps is perpendicular to qr and rt is perpendicular to pq. If the length of ps is 5 cm, find the area of triangle pqr. What will be the length of rt?

Answer 1

Given : isosceles triangle with pq = pr = 7 cm and qr = 12 cm.

Ps is perpendicular to qr and

rt is perpendicular to pq.

the length of ps is 5 cm,

To find : the area of triangle pqr.

length of rt?

Solution:

isosceles triangle with pq = pr = 7 cm and qr = 12 cm.

Ps is perpendicular to qr

Area of Δpqr  = (1/2) qr * ps

= (1/2) * 12 * 5

= 30  cm²

Area of Δpqr  =   (1/2) * pq * rt

= (1/2) * 7 * rt  = 30

=> rt = 60/7 cm

But there is mistake in Data

as qr = 12 cm

=> qs = rs = 12/2 = 6 cm  

ps = 5 cm

=> pq = qr = √6² + 5² = √61 = 7.81  cm  not 7 cm

Learn More

find the area of triangle having vertices at (8,1)

brainly.in/question/12350448

Find the area of the triangle formed by the straight lines 2x - y - 5=0, x

brainly.in/question/11710045