Th sum of ages of father and is sons 60 years. After 14 years , fathers age will be three times the age of the son. Find their present ages
Answers
Answered by
71
Hi there!
here's the answer :
let father's age be x
son's age = 60-x
(since sum of their both ages = 60)
After 14 years,
father's age= x+14
son's age = 60-x+14= 74-x.
Given,
Fathers age= 3(age of his son)
=> x+14= 3(74-x)
=> x+14= 222-3x
=> 4x= 208
=> x= 52
•°• Father's age x= 52
and Son's age 60-x= 60-52= 8.
:)
Hope it helps
here's the answer :
let father's age be x
son's age = 60-x
(since sum of their both ages = 60)
After 14 years,
father's age= x+14
son's age = 60-x+14= 74-x.
Given,
Fathers age= 3(age of his son)
=> x+14= 3(74-x)
=> x+14= 222-3x
=> 4x= 208
=> x= 52
•°• Father's age x= 52
and Son's age 60-x= 60-52= 8.
:)
Hope it helps
Answered by
24
suppose present age of son be x
so present age of father=60-x
After 14 years the age of son=x+14
and that of father=74-x
As per question, 74-x=3(x+14)
or74-x=3x+42
or,4x=32
or,x=8 son age
father age=60-8=52year.
so present age of father=60-x
After 14 years the age of son=x+14
and that of father=74-x
As per question, 74-x=3(x+14)
or74-x=3x+42
or,4x=32
or,x=8 son age
father age=60-8=52year.
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