Th sum of three consecutive multiples of 5 is 120. Find the three integers.
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Th sum of three consecutive multiples of 5 is 120. Find the three integers.
Let the first number be X
Then the second number is x+ 5
Then the third number is x+ 10
Now we are given that the sum of the three terms is 120.
==> x + x+ 5 + x+ 10 = 120
==> 3x + 15 = 120
Now we will subtract 15 .
==> 3x = 105
Now we will divide by 3.
==> x = 35
Then the numbers are: 35, 40 , and 45.
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