Question

th Two numbers are in the ratio 7:11.
if 7 is added to each of the
numberti
the ratio becomes 2:3
find the numbers​

Answer 1

Answer:

7x+7/11x+7=2/3

21x+21=22x+14

7=x

numbers are 49,77

Answer 2

Step-by-step explanation

Here, a = 7, b = 11, x = 7, c= 2, d = 3

1st Number= xa(c − d)/ad − bc

= 7 × 7(2 − 3)/7 × 3 − 11 × 2

=49 × −1/21 − 22=49

2nd Number = xb(c − d)/ad − bc

=

7 × 11(2 − 3)/7×3-11×2

=77-1/21-22=77

smallest number=49

hope it will help you!!