Question

tha
0
a lies in Il quadrant, then find
If tanx = - 4
3
sin a
value of
2
て​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

tanx/2 =2

Step-by-step explanation:

As tanx = –3/4 , 2/π <x<π

i.e x lies in 2nd quadrant

Hence tanx=−

3/4 ⇒sinx= 4 /2 +3 /2/4 = 5/4

And cosx=−

4 /2 +3 /2

/5 =− 5/3

Now using 1−cosx=2sin /2

2/x ⇒sin 2/x =± 2

1−cosx

, we get

sin 2/x =± 2/1−(− 5/3) =± 10/8

As

2/π <x<π⇒4/π < 2/x < 2/π and sine is positive in 1st quadrant

Then sin

2/x = 5/2

Using 1+cosx=2cos /2

2/x ⇒cos 2/x =± 2/1+cocos

We get, cos

2/x =± 21+(− 5/3 ) =± 10/2

2/π<x<π⇒ 4/π < 2/x< 2/π

and cos is positive 1st quadrant

∴cos 2/x = 5/1

Using cosx= 1+tan /2

2/x

x1−tan 2

2/x ⇒tan 2/x =± 1+cosx1−cosx

We get, tan

2/x =± 1+(− 5/3 )1−(− 5/3 ) =± 4

As 2/π<x<π⇒ 4/π< 2/x < 2/π

and tan is positive in 1st quadrant

∴tan2x=2