Question

Tha 7th term of an A.p is 32 and 13th term is 62 .Find the A. P.

Answer 1

given,
7th term of AP= 32
=> a+ (7-1)d = 32
=> a +6d= 32. ___(1)
and,
13th term of AP= 62
=> a+ (13-1)d = 62
=> a+12d = 62 ___ (2)

eq.(2) - eq(1)
6d = 30
=> d = 5

put d= 5 in equation (1)
we get, a = 2
we know that AP is in the form of a, a+d, a+2d...
so the AP will be
2, 7, 12, 17...

Answer 2

a7 = 32        a13 = 62
                                        a7 = a + 6d= 32       
                                        a13 = a + 12d= 62
by elimination method,
                                          -6d = -30
  .                                              d=5,  a=2
.   .   AP = 2, 7,12, 17..........