Question

दो अंको की संख्या के अंकों का योग 8 है यदि संख्या के अंकों के क्रम को उलट देने पर प्राप्त हुई संख्या पहली संख्या से 18 कम हो जाती है संख्या ज्ञात कीजिए​

Answer 1

Answer:

Step-by-step explanation:

question in english

The sum of the digits of the two-digit number is 8 if the number obtained by reversing the order of the digits of the number is reduced by 18 from the first number. Find the number.

answer in english

I am assuming you are a school student, hence I will try a very basic approach.

So the first thing is what does a two digit number look like?

Any two digit number can be written in the form  10x+y  

In this particular case, you have your  x+y=8−−−(1)  

After reversing, our number becomes  10y+x  

Now note that the difference between the number and that formed by reversing the digits is 18 so:

(10x+y)−(10y+x)=18  

=> 10x+y−10y−x=18  

=>  9x−9y=18  

=>  x−y=2−−−−(2)  

So now you have two equations (1) and (2)

Simply add them :D

x−y=2  

x+y=8  

=>2x=10  

=> x=5  

So just plug in your  x  into any of the equations and you get the value of  y  

I, for instance am taking eq (1)

so we have,

x+y=8  

=> 5 +y=8  

=>  y=3  

So the number is :

(10∗5)+3=53  

Hope this helped. :)