Question

दिए गए बहु पदों के गुणनखंड ज्ञात करो​

Answer 1

Answer:

v

Step-by-step explanation:

Answer 2

$\small\red{\boxed{Question .1 = {x}^{2} + 3x + 2 }} \\ \: \color{orange}solution : - \\ \\ \color{blue} = {x}^{2} + 3x + 2 \\ \\ \color{blue} = {x}^{2} + (2 + 1)x + 2 \\ \\ \color{blue} = {x}^{2} + 2x + x + 2 \\ \\ \color{blue} = x(x + 2) + 1(x + 2) \\ \\ \small\green{\boxed{ = (x + 2)(x + 1) \: \: is \: the \: answer}} \\ \\ \\ \small\red{\boxed{Question .2 = 2 {x}^{2} + 8x + 8}} \\ \color{orange}solution : - \\ \\ \color{blue} =2 {x}^{2} + 8x + 8 \\ \\ \color{blue} =2 {x}^{2} + (4 + 4)x + 8 \\ \\ \color{blue} =2 {x}^{2} + 4x + 4x + 8 \\ \\ \color{blue} =2x(x + 2) + 4(x + 2) \\ \\ \small\green{\boxed{=(2x + 4)(x + 2) \: \: is \: the \: answer}} \\ \\ \\ \small\red{\boxed{Question .3 = 3 {x}^{2} + 13x + 12 }} \\ \\ \color{orange}solution : - \\ \\ \color{blue} =3 {x}^{2} + 13x + 12 \\ \\ \color{blue} =3 {x}^{2} + (9 + 4)x + 12 \\ \\ \color{blue} =3 {x}^{2} + 9x + 4x + 12 \\ \\ \color{blue} =3x(x + 3) + 4(x + 3) \\ \\\small\green{\boxed{ =(3x + 4)(x + 3) \: \: is \: the \: answer }}\\ \\ \\ \small\red{\boxed{Question .4 = {x}^{2} - x - 12}} \\ \color{orange}solution : - \\ \\ \color{blue} = {x}^{2} - x - 12 \\ \\ \color{blue} = {x}^{2} - (4 - 3)x - 12 \\ \\ \color{blue} = {x}^{2} - 4x + 3x - 12 \\ \\ \color{blue} =x(x - 4) + 3(x - 4) \\ \\ \small\green{\boxed{ =(x + 3)(x - 4) \: \: is \: the \: answer}} \\ \\ \\ \small\red{\boxed{Question .5= 2 {x}^{2} - 8x + 8 }} \\ \color{orange}solution : - \\ \\\color{blue} =2 {x}^{2} - 8x + 8 \\ \\ \color{blue} =2 {x}^{2} - (4 + 4)x + 8 \\ \\ \color{blue} =2 {x}^{2} - 4x - 4x + 8 \\ \\ \color{blue} =2x(x - 2) - 4(x - 2) \\ \\ \small\green{\boxed{ =(2x - 4)(x - 2) \: \: is \: the \: answer}} \\ \\ \\ \small\red{\boxed{Question .6= 2 {x}^{2} + 7x + 3 }} \\ \color{orange}solution : - \\ \\ \color{blue} =2 {x}^{2} + 7x + 3 \\ \\ \color{blue} =2 {x}^{2} + (6 + 1)x + 3 \\ \\ \color{blue} =2 {x}^{2} + 6x + x + 3 \\ \\ \color{blue} =2x(x + 3) + 1(x + 3) \\ \\ \small\green{\boxed{ =(2x + 1)(x + 3) \: \: is \: the \: answer}} \\ \\ \\ \small\red{\boxed{Question .7=6 {x}^{2} + 5x - 6}} \\ \color{orange}solution : - \\ \\ \color{blue} =6 {x}^{2} + 5x - 6 \\ \\ \color{blue} =6 { x }^{2} + (9 - 4)x - 6 \\ \\ \color{blue} =6 {x}^{2} + 9x - 4x - 6 \\ \\ \color{blue} =3x(2x + 3) - 2(2x + 3) \\ \\ \small\green{\boxed{ = (3x - 2)(2x + 3) \: \: is \: the \: answer}} \\ \\ \\ \small\red{\boxed{Question .8=2 {x}^{2} - 10x + 8}} \\\color{orange}solution : - \\ \\ \color{blue} =2 {x}^{2} - 10x + 8 \\ \\ \color{blue} =2 {x}^{2} - (8 + 2)x + 8 \\ \\ \color{blue} =2 {x}^{2} - 8x - 2x + 8 \\ \\\color{blue} =2x(x - 4) - 2(x - 4) \\ \\ \small\green{\boxed{ =(2x - 2)(x - 4) \: \: is \: the \: answer}} \\ \\ \small\purple{\underline{\underline{hope \: its \: help \: you \: dear \:✌✌☺☺❤ }}} \\ \\ \\ \small\pink{ \underline{\boxed{ \underline{\boxed{ \underline{@ ᭄亗 乄 ＭꫝղᎥនh 乄 亗✯❤࿐}}}}}}$