Question

दिए गए चित्र में प्रतिरोधकों ,R1 =5 Ω, R2=10 Ω, R3=30 Ω को 12 V की बैटरी से संयोजित किया गया है।परिकलित कीजिए-- (a)प्रत्येक प्रतिरोध से प्रवाहित विद्युत धारा व (b)परिपथ में प्रवाहित कुल विद्युत धारा|

Answer 1

Answer:

The equivalent resistance of the 5Ω, 10Ω, 30Ω resistors connected in parallel is

R

p

1

=

5

1

+

10

1

+

30

1

=

30

6+3+1

=

30

10

∴R

p

=3Ω

∴, the total resistance of the given circuit is 3 Ohms.

The total current can be calculated using the Ohm's law as the value of voltage (V) is already given.

using Ohm's law

Voltage=Current×Resistance

⇒I=

R

V

=

3

12

=4A

Current through each resistor can be calculated by applying Ohm's law given that the voltage of the circuit and the individual resistances of each resistor is already given.

Current through 5Ω resistor =

R

V

=

5

12

=2.4A

Current through 10Ω resistor =

R

V

=

10

12

=1.2A

Current through 30Ω resistor =

R

V

=

30

12

=0.4A