Math, asked by anirudhduhoon97, 6 months ago

द एरिया ऑफ स्क्वायर फील्ड 7,20,801 मीटर पर स्क्वायर एमएम साइकिलिंग हेलो इट्स बाउंड्री 18 किलोमीटर पर आवर इन हाउ मच टाइम विल बे रिटन द स्टार्टिंग प्वाइंट​

Answers

Answered by klakshyakr2020
0

Answer:

He will return to starting point in 196 seconds.

Step-by-step explanation:

Area of square field = 60025 sq.m.

Area of square = Side ^2Side

2

So, 60025=Side ^260025=Side

2

\sqrt{60025}=Side

60025

=Side

245=Side245=Side

Since we are given that he cycles along the boundary of field

So, Perimeter of square field =4 \times Side4×Side

Perimeter of square field =4 \times 2454×245

Perimeter of square field =980 m980m

So, Total distance = 980 m

Speed = 18 km/h =18 \times \frac{5}{18} =5 m/s18×

18

5

=5m/s

Time =\frac{Distance}{Speed}Time=

Speed

Distance

Time =\frac{980}{5}Time=

5

980

Time =196Time=196

Hence he will return to starting point in 196 seconds.

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