Question

दी गई समीकरण के वास्तविक मूलों के संख्या होगी ) (x+1)²-x²=0 :
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Answer 1

Answer:

${(x + 1)}^{2} - {x}^{2} = 0 \\ \\ = > {x}^{2} + 2x + 1 - {x}^{2} = 0 \\ \\ = > 2x + 1 = 0 \\ \\ ( {x}^{2} \: and \: - {x}^{2} \: cancelled) \\ \\ = > 2x = - 1 \\ \\ = > x = \frac{ - 1}{2}$

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Answer 2

Answer:

समीकरण के वास्तविक मूलों के संख्या होगी ) (x+1)²-x²=0 :