Question

दी गई समीकरण में k का मान ज्ञात करें जिस के लिये समीकरण के मूल बराबर हों: kx²+ 6x + 1 = 0 *​

Answer 1

Step-by-step explanation:

ANSWER

The dimensions of cuboid are 50×40×25

The Lateral surface area of cuboid is given by 2h(l+b)

Here l=50;b=40;h=25

Lateral surface area is 2×25(50+40)=50(90)=4500

And the base area is given by lb=(40)(50)=2000

So The total area is given by 4500+2000=6500

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