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दो इसी तरह और समान रूप से आरोप लगाया समान धातु एक क्षेत्रों और ख 2 एक्स 10-6 n एक तिहाई समान आरोप लगाया क्षेत्र ग वाले बल के साथ एक दूसरे को विकर्षित एक साथ छुआ है और उसके बाद मध्य एक के बीच बिंदु पर रखा जाता है​

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student-name Shaswatarchanasantosh.shukla asked in Physics

Two similarly and equally charged identical metal spheres A and B repel each other with a force of 0.000002 N. A third identical sphere C is touched with A and then placed at the mid point between A nd B. What is the net electric force on C?

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student-name Ishan Goyal answered this

1072 helpful votes in Physics, Class XII-Commerce

Let the charge on A and B be = Q each.

Let the distance of separation between them be = 2R

According to Coloumb’s law of electrostats,

Force between them F1 = KQ2/(2R)2

F1 = KQ2/4R2 this force is given in the problem as 2*10-5N.

When an uncharged sphere C is brought in contact with A first, the charges get equally shared between them , hence each sphere acquires a charge Q/2.

Now force between A &C after it is placed at mid point ie at distance R from A is:

F2 = K(Q/2 )*( Q/2)/R2

F2 = KQ2/4R2

Force between C and B will be :

F3 = (K(Q/2) * Q)/(R)2

F3 = KQ2/2R2

Clearly, F3>F2 therefore F3-F2:-

Hence KQ2/R2( 1/2 - 1/4 )

= KQ2/R2( ¼ )

= KQ2/4R2

But this is the given force F1 from eqn 1 hence the net force on C = 2*10-5N

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