Question

दिलेलं वर्गसमीकरण पूरण वर्ग पद्धतीने सोडवा: 9y² - 12 y + 2 = 0

Answer 1

Answer:

y = (2+√2)/3 or y= (2-√2)/3

Explanation:

9y²-12y+2 = 0

=>9y² -12y = -2

On dividing each term by 9,

we get

=> y² - 4y/3 = -2/9

=> y² - 2*y*(2/3) = -2/9

=> y² -2*y*(2/3)+(2/3)²=-2/9+(2/3)²

=> (y-2/3)² = -2/9+4/9

=> (y-2/3)² = 2/9

=> y -2/3 = ±√(2/9)

=> y = 2/3±√2/3

=> y = (2±√2)/3

Therefore,

y = (2+√2)/3 or y= (2-√2)/3

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