दिलेलं वर्गसमीकरण पूरण वर्ग पद्धतीने सोडवा: 9y² - 12 y + 2 = 0
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Answer:
y = (2+√2)/3 or y= (2-√2)/3
Explanation:
9y²-12y+2 = 0
=>9y² -12y = -2
On dividing each term by 9,
we get
=> y² - 4y/3 = -2/9
=> y² - 2*y*(2/3) = -2/9
=> y² -2*y*(2/3)+(2/3)²=-2/9+(2/3)²
=> (y-2/3)² = -2/9+4/9
=> (y-2/3)² = 2/9
=> y -2/3 = ±√(2/9)
=> y = 2/3±√2/3
=> y = (2±√2)/3
Therefore,
y = (2+√2)/3 or y= (2-√2)/3
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